Question

If 1/2 is a root of the quadratic equation x² -mx-5/4=0, then value of m is *
1/2
2
-2
- 1/2​

Answer 1

Answer:

m=-2

Step-by-step explanation:

p(x)=x^2-mx-5/4

p(1/2)=(1/2)^2-m×1/2-5/4=0

1/4-m/2-5/4=0

-m/2-4/4=0

-m/2-1=0

-m/2=1

-m=2

m=-2

Answer 2

Answer:

Your answer is -2

Step-by-step explanation:

Put, x = (1/2)

Now,

Equation= x^2 - me - 5/4 =0

(1/2)^2 -m(1/2) - 5/4 =0

(Find LCM of 2, 2 and 4 of denominators = 4)

We get, LCM = 4

By multiplying by 4 both sides,

(1/4) × 4 - (m/2) × 4 - (5/4) × 4 = 0×4

1 - 2m - 5 =0

-2m = 5-1

-2m = 4

- m = (4/2) =2

-m = 2

Or

m = -(2)