Question

if -1/2 is a solution of kx^2-3x-k=0 find k.

Answer 1

Putting x=-1/2 in given equation

K(1/2)²-3×(-1/2)-k=0

k/4+3/2-k=0

-3/4k=-3/2

so k=2

I hope it helps you

Answer 2

FRiend,

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Question: If -1/2 is a solution of kx^2-3x-k=0 find k.

Solution:

Since $\frac{-1}{2}$ is the solution if the equation It will satisfy the equation.

$\boxed{kx^2-3x-k= 0 }$

substituting $\frac{-1}{2}$ in this equation.

k$\frac{-1}{2} ^{2}$  -3 ( $\frac{-1}{2}$)  - k = 0

$\frac{k}{4}$ + $\frac{3}{2}$ -k =0

$\frac{3k}{4}$ = $\frac{3}{2}$

$\boxed{ k = 2 }$

so the value of k is 2.

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Hope this helps you

Regards