Question

If -1/2 is a zero of the polynomial 3x^3+x^2-6x-3, find the sum the of its other two zeroes.

Answer 1

$\huge{\mathfrak{SOLUTION}}$

As we know,

$\alpha + \beta + \gamma = \frac{ - b}{a}$

As one zero is -1/2

Now,

α+β+(-1/2) = -1/6

α+β = -1/6 + 1/2

α+β = 2/6

α+β = 1/3