if 1/2 is a zero of the polynomial p(x)=2xsquare3 +ax square +11x +a+3,find the value of a
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Answered by
15
Since 1/2 is a zero, substitute x = 1/2 in 2x³ + ax² + 11x + a+ 3 = 0
2(1/8) + a (1/4) + 11(1/2) + a + 3 = 0
1/4 + a/4 + 11/2 + a + 3 = 0
35/4 + 5a/4 = 0
5a = -35
a = -7
2(1/8) + a (1/4) + 11(1/2) + a + 3 = 0
1/4 + a/4 + 11/2 + a + 3 = 0
35/4 + 5a/4 = 0
5a = -35
a = -7
Answered by
7
p(x)=2x³+ax²+11x+(a+3)
=>0=2x³+ax²+11x+(a+3)
=>0=2×(1/8)+a/4+11/2+(a+3)
=>1/4+5a/4+(11/2)+3=0
=>5a/4=-(1/4+11/2)-3
=>5a/4=-(23/4)-3
=>5a=-35
=>a=-7
=>0=2x³+ax²+11x+(a+3)
=>0=2×(1/8)+a/4+11/2+(a+3)
=>1/4+5a/4+(11/2)+3=0
=>5a/4=-(1/4+11/2)-3
=>5a/4=-(23/4)-3
=>5a=-35
=>a=-7
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