if -1/2 is one of the root of quadratic equation 2x2+kx+1=0 find k.
class 10 maths ch-4
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Answered by
3
Hey
Here is your answer,
Substitute the value of x in equation,
2x^2 + kx + 1 = 0
2 ( -1/2 )^2 + (-1/2)k + 1 = 0
2 x 1/4 - k/2 + 1 = 0
1/2 - k/2 + 1 = 0
1-k/2 + 1 = 0
1 - k + 2 = 0
-k + 3 = 0
-k = -3
k = 3
Hope it helps you!
Here is your answer,
Substitute the value of x in equation,
2x^2 + kx + 1 = 0
2 ( -1/2 )^2 + (-1/2)k + 1 = 0
2 x 1/4 - k/2 + 1 = 0
1/2 - k/2 + 1 = 0
1-k/2 + 1 = 0
1 - k + 2 = 0
-k + 3 = 0
-k = -3
k = 3
Hope it helps you!
Radheyshyamshah:
ok
Answered by
1
Here is your answer
2x²+kx+1 = 0
2 × (-1/2)² + k × -1/2 + 1 = 0
2 × 1/4 - k/2 + 1 = 0
1/2 - k/2 + 1 = 0
1 - k + 2 = 0
-k + 3 = 0
-k = -3
k = 3
Hope it helps you ^_^
Mark as brainliest.
2x²+kx+1 = 0
2 × (-1/2)² + k × -1/2 + 1 = 0
2 × 1/4 - k/2 + 1 = 0
1/2 - k/2 + 1 = 0
1 - k + 2 = 0
-k + 3 = 0
-k = -3
k = 3
Hope it helps you ^_^
Mark as brainliest.
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