if 1 / 2 is root of equation X^2 + kx - 5 / 4 = 0 then find k
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refer the attachment
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apurva06:
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Hi...☺
Here is your answer...✌
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Let p(x) = x² + kx - 5/4
Given : 1/2 is the root of p(x)
=> p(1/2) = 0
(1/2)² + k(1/2) - 5/4 = 0
1/4 + k/2 - 5/4 = 0
k/2 - 4/4 = 0
k/2 -1 = 0
k/2 = 1
k = 2
Here is your answer...✌
=================================
Let p(x) = x² + kx - 5/4
Given : 1/2 is the root of p(x)
=> p(1/2) = 0
(1/2)² + k(1/2) - 5/4 = 0
1/4 + k/2 - 5/4 = 0
k/2 - 4/4 = 0
k/2 -1 = 0
k/2 = 1
k = 2
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