Math, asked by seesaw, 1 year ago

if 1/2 is the root of the equation x²+kx-5/4=0, find the value of k

Answers

Answered by jeshwika
9
hey frnd......


one root is x=1/2


sub this value in equation



x^2+kx-5/4=0


(1/2)^2+k(1/2)-5/4=0

1/4+k/2-5/4=0

k/2-4/4=0

k/2-1=0

k/2=1

k=2



sure it right answer............
Answered by shashankavsthi
24
\blue{Answer}
root \: of \: the \: given \: equation \: is \: \frac{1}{2} \\ \\ equation \: is - \\ {x}^{2} + kx - \frac{5}{4} = 0 \\ \\ since \: \frac{  1}{2} \: is \: root \: so \: put \: value \: - \frac{1}{2} in \: place \: of \: x \\ \\ {( \frac{ 1}{2} )}^{2} + k(  \frac{1}{2} ) - \frac{5}{4} = 0 \\ \frac{1}{4} + \frac{k}{2} - \frac{5}{4} = 0 \\ \\  2k = 4 \\ k =  2
\pink{\underline{Hope\: it will\: be\: helpful\:for\: you}}

shashankavsthi: oops put -1/2 as root my mistake
jeshwika: edit right now
shashankavsthi: edited!!
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