Question

if 1/2 is zero of polynomial p(x)=2x^4-ax^3+4x^2+2x+1 find the value of a.
please refer to the attachment

Answer 1

$p(x) = 2x {}^{4} - ax {}^{3} + 4x {}^{2} + 2x + 1$
If 1/2 is the zero of polynomial.
then, p(1/2)=0
$p( \frac{1}{2} ) = 2 \times ( \frac{1}{2} ) {}^{4} - a \times ( \frac{1}{2} ) {}^{3} + 4 \times ( \frac{1}{2} ) {}^{2} \\ + 2 \times \frac{1}{2} + 1 = 0 \\ \frac{1}{8} - \frac{a}{8} + 1 + 1 + 1 = 0 \\ \frac{1}{8} + 3 = \frac{a}{8} \\ \frac{1 + 24}{8} = \frac{a}{8} \\ \frac{25}{8} = \frac{a}{8} \\ a = \frac{25 \times 8}{8} = 25$

Answer 2

simple answer 25 main jo mikal ke aata hai last ka ek dam