Geography, asked by yashkirtijha2234, 10 months ago

if 1/2 is zero of the polynomial p(x)=8x^3+ax^2-4x+2​

Answers

Answered by Anonymous
5

Answer :

a = - 4

Explanation:

If 1/2 is a zero of the above p(x). On substituting it back in the equation would give zero as a solution of all calculations

Given Polynomial,

 \sf \: p(x) =  {8x}^{3}  + a {x}^{2}  - 4x + 2

To finD

Value of a

Now,

 \sf \: p( \dfrac{1}{2} ) = 8( \dfrac{1}{2}) {}^{3}   + a (\dfrac{1}{2} ) {}^{2}  - 4 \times  \dfrac{1}{2}  + 2 \\  \\  \longrightarrow \:  \sf \: \: 0 = 8 \times  \dfrac{1}{8}  +  \dfrac{a}{4}    - \cancel{2} \:  +  \cancel{2} \\  \\  \longrightarrow \:  \sf \:  \dfrac{a}{4}  =  - 1 \\  \\  \longrightarrow \:   \underline{ \boxed{\sf {a =  - 4}}}

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