if (1/2)^k=(3)^1/2 &(1/3)^m=(2)^1/2 find (mk/2)
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think the pattern followed is n3+nn3+n
So, 1=13+1=1+1=21=13+1=1+1=2
2=23+2=8+2=102=23+2=8+2=10
3=33+3=27+3=303=33+3=27+3=30
4=43+4=64+4=684=43+4=64+4=68
Going by that,
5=55=53+5=125+5=130
So, 1=13+1=1+1=21=13+1=1+1=2
2=23+2=8+2=102=23+2=8+2=10
3=33+3=27+3=303=33+3=27+3=30
4=43+4=64+4=684=43+4=64+4=68
Going by that,
5=55=53+5=125+5=130
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