If (1/2) of A=(2/5) of B=(1/3)of C, then find A:B:C
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Solution :-
Given that , (1/2) A = (2/5)B = (1/3) C .
So , let us take ,
❒ ½ A = ⅖B = ⅓ C = k .
So ,now we can write them as ;
(i) => ½ A = k
=> A = 2k .
(ii) => ⅖ B = k.
=> B = 5/2k .
(iii) => ⅓ C = k
=> C = 3k .
So , now A:B:C = 2k : 5/2k : 3k .
=> Ratio = 2k : 5/2k : 3k .
=> Ratio = 2 ( 2k : 5/2k : 3k ) .
=> Ratio = 4k : 5k : 6k.
=> A : B : C = 4 : 5 : 6 .
Hence the required ratio is 4:5:6 .
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