Question

If 1/2 of the air in a tank is removed with each stroke
of a vacuum pump, what fraction of the original
amount of air has been removed after 4 strokes?​

Answer 1

answer:

15/16

Step-by-step explanation:

let vol. of tank =x

vol. remain after 4 stokes = x×1/2×1/2×1/2×1/2=x/16

vol. removed=x-x/16

=15x/16

: 15/16

Answer 2

If 1/2 of the air in a tank is removed with each stroke

of a vacuum pump, what fraction of the original

amount of air has been removed after 4 strokes?