Question

If 1.26 g oxalic acid dissolve in 500 gm water. calculate normality of resultant solution.(density=1.1gm/cm^3.)​

Answer 1

Explanation:

normality =n-factor×molarity

molar mass of oxalic acid =126g

density=mass/vol

vol of sol=500/1.1=454ml

moles=1.26/126=0.01

molarity=0.01×1000/454=0.022M

n-factor in acids calculated by number of acidic hydrogen

in oxalic acid n-factor=2

normality=2×0.022=0.044N