If {1+27/169}^1/2=(1+x/13) find the value of x
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Step-by-step explanation:
=> √(1+27)/169 = 1+x/13
=> 1+√27/13 = 1+x/13
=> 13(1+√27)= 13(1+x)
=> 13+13√27= 13+13x
=> 13√27-13x=13-13
=> 13√27 - 13x = 0
=> -13x = -13√27
=> x = -13√27/-13
=> x = √27
Hope it helps you.....
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