If 1.27gm Cu is obtained by reduction of one sample of cu2o then the amount of oxygen in sample is .... gm
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↪ hence cu : o (in cu2o) = 2:1
️↪️ 1.27 : 1.27/2
↪️6.37
↪️hence amount of oxygen in sample = 6.37 gm
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this is your answer thank you for your question
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