if 1/2a root of equation xsq+kx=0 then value of k is
Answers
Answer:
The value of K is 2.1
To find the value of K the first thing to be done is to observe the quadratic equation given and then substitute the value of the X and equate it to zero then the value of K will be found.
Let z be the root of the equation F(X), then F(Z) = 0. Similarly, when we substitute \frac{1}{2}
2
1
in the given equation X^{2}+K X-\frac{s}{4}=0X
2
+KX−
4
s
=0 which results the value should be zero.
\Rightarrow\left(\frac{1}{2}\right)^{2}+K\left(\frac{1}{2}\right)-\frac{5}{4}=0⇒(
2
1
)
2
+K(
2
1
)−
4
5
=0
\Rightarrow \frac{1}{4}+\frac{K}{2}-\frac{5}{4}=0⇒
4
1
+
2
K
−
4
5
=0
\Rightarrow 1+2 K-5=0⇒1+2K−5=0
\Rightarrow K=2.1⇒K=2.1
Step-by-step explanation:
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Answer:
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