If (1+2i) (1+3i) (2+i) then a+ib form is
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Given :-
( 1 + 2i ) ( 1 + 3i ) ( 2 + i ) .
To Find :-
The given in the form of a + ib .
Used Concepts :-
- Value of iota i.e √-1 and that of i² i.e -1 .
Solution :-
Here , ( 1 + 2i ) ( 1 + 3i ) ( 2 + i )
At first , we will multiply two factors then the third with the product of two factors .
[ ( 1 + 2i ) × ( 1 + 3i ) ] × ( 2 + i )
=> [ 1 × ( 1 + 3i ) + 2i × ( 1 + 3i ) ] × ( 2 + i )
=> [ 1 + 3i + 2i + 6i² ] × ( 2 + i )
=> [ 1 + 5i + 6 × -1 ] × ( 2 + i )
=> [ 1 + 5i - 6 ] × ( 2 + i )
=> ( 2 + i ) × ( 5i - 5 )
=> 2 × ( 5i - 5 ) + i × ( 5i - 5 )
=> 10i - 10 + 5i² - 5i
=> 5i - 10 + 5 × -1
=> 5i - 10 - 5
=> -15 + 5i = -15 + i5
Hence , it is in the form of a + ib , where a = -15 and b = 5 .
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