Question

if 1 + 2sin²θ cos²θ = sin² + cos² + 4k sin²θ cos²θ, then k = __​

please help me if yk :3

Answer 1

k =1/2

Explanation:

1+2sin²θcos²θ = 1+4k sin²θcos²θ

2sin²θcos²θ = 4k sin²θcos²θ

2sin²θcos²θ/sin²θcos²θ = 4k

2 = 4k

k=1/2

Answer 2

The value of k is 1/2
Hope you got it :)