Question

if 1^3+2^3+....+a^3=5041.find 1+2+3+....+a

Answer 1

Answer:

71

Step-by-step explanation:

let sum of series 1³+2³+3³..........a³ be S

∴ S = 1³+2³+3³+..........+a³ = 5041

Sum of term of this sequence is [n(n+1)/2]².................eqⁿ (i)

let sum of series 1+2+3..........a be M

∴ M = 1+2+3+.........+a

Sum of term of this sequence is [n(n+1)/2].................eqⁿ (ii)

From eqⁿ (i)

[n(n+1)/2]² = 5041

[M]² = 5041

∴ M = 71

Sum of series 1+2+3+4..............+a is 71

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