Question

If 1/3*(3/4+-4/5)=1/3*X+Y*-4/5 then X+Y=?​

Answer 1

Answer:

13/12 is the write ans for above question

Answer 2

Given expression is $1/3*(3/4+(-4/5)=1/3*X +Y*(-4/5)$

 We have to find  $x+y$ w,e get

 In left side, multiplying $\frac{1}{3}$ to the bracket term$(\frac{3}{4}-\frac{4}{5} )$  and after solving bracket ,

we get $\frac{1}{3} \times (\frac{1}{20})$

In right side , multiplying $\frac{1}{3}$ by $(\frac{-4}{5} )$ it get $(\frac{-4}{15} )$

∴ $\frac{1}{3} \times (\frac{1}{20} )$$=x+y[(\frac{-4}{15} )]$

multiplying $3$ by both the terms ,we get

$\frac{1}{1} \times \frac{1}{20} =(x+y)\times (\frac{-4}{5})$

now, again multiplying both side by $5$, we get

$\frac{1}{4} =(x+y)(\frac{-4}{1} )$

∴$x+y =-\frac{1}{16}$

Therefore, $-\frac{1}{16}$ is a required answer.