Math, asked by srikanta4, 1 year ago

if 1*3*5=1925 and 7*9*11=4981121, then find the value of 19*21*23=?

Answers

Answered by Anonymous
1
19^2 is 361
21^2 is 441
23^2 is 529
so if we multiple them we get
361*441*529= 361441529
Answered by Anonymous
0
hlo frnd
ur answer is 361441529
it's simple :-
let's c
1*3*5=1925
1^2=1
3^2=9
5^2=25
write all the results together : 1925
7*9*11=4981121
7^2=49
9^2=81
11^2=121
so the answer is 7*9*11=4981121
in the same way
19^2=361
21^2=441
23^2=529
so ur answer is 361441529
hope it helps u
mark it as brainliest if you are satisfied with my answer :-)
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