Question

If 1,3,5,7.....is a sequence Then please explain this line T1= 1, Tn+1= Tn+2

Answer 1

1,3,5,7... is an AP ARITHMETIC PROGRESSION

with first term 1 i.e. T1(a)=1

Common difference(d) =2

Here n can be any number of term

And Tn=a+(n—1)d

Using this formula u can find values of the AP at any position

Hope it helps you

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