Question

if 1+3+5+....to n term/2+5+8+...to 8 terms =9 ; then find the value of n.

Answer 1

sum of odd no up to n terms =
${n}^{2}$
$1 + 3 + 5 + ...........n = {n}^{2}$
${n }^{2} \div 2 + 5 + 8 + ...... + 23$

Answer 2

9=1+(n-1)2
9=1+2n-2
9+2=1+2n
11-1=2n
10=2n
10/2=n
5=n