Question

if 1/3 is a zero of polynomial 3x3-4x2-17x+k then find the value of k​

Answer 1

Answer:

Step-by-step explanation:

F(x)=3x3-4x2-17x+k

F(1/3)=3×(1/3)^3-4×(1/3)^2-17×1/3+k=0 ( as 1/3 is a root )

F(1/3)=1/9-4/9-17/3+k=0

F(1/3)=-3/9-17/3+k=0

F(1/3)=-54/9=-k

F(1/3)=6=k

Hence k=6