If 1/3 is a zero of the polynomial 3x3 – 4x2 – 17x – k , then find the value of k.
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Answered by
4
If 1/3 is a zero of given polynomial so on putting the value of x in the equation as 1/3 the whole equation will be equal to 0 .
P(x) = 3x3-4x2-17x-k
P(1/3) = 3(1/3)3-4(1/3)2-17(1/3)-k = 0
= 1/9-4/9-17/3-k=0
= -54/9-k=0
k= -6
THAT'S your answer
P(x) = 3x3-4x2-17x-k
P(1/3) = 3(1/3)3-4(1/3)2-17(1/3)-k = 0
= 1/9-4/9-17/3-k=0
= -54/9-k=0
k= -6
THAT'S your answer
Answered by
1
Answer:
7
Step-by-step explanation:
One zero is 1/3then,
3×(1/3)^3-4×(1/3)^2-17×(1/3)+k =0
1/9 -4/9-17/3+k=0
(1+4+51+k)/9=0
1-55+9k=9
-54+9k=9
9k=9+54
k=63/9
k=7
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