Question

If (-1/3) is a zero of the polynomial p(x)=27x^3-ax^2+x+3 then find the value of a

Answer 1

Answer:

Step-by-step explanation:

If -1/3 is zero of polynomial then

P(-1/3) = 27(-1/3)^3-a(-1/3)^2+(-1/3)+3=0

27×(-1/27)-a(1/9)-1/3+3=0

-1-a/9-1/3+3=0

-a/9-1/3-1+3=0

-a/9+5/3=0

-a/9=-5/3

a=9×5/3

a=15