Question

If -1/3 is one of the zeroes of 9x^2 - Kx -5 then the value of k is

Answer 1

Answer:

$9 x {}^{2} - kx - 5 \\ put \: the \: value \: of \: x = \frac{ - 1}{3} \\ \\ 9( \frac{ - 1}{3}) - k( \frac{ - 1}{3} ) - 5 = 0 \\ \\ 3 \times - 1 + \frac{k}{3} - 5 = 0 \\ \\ - 3 + \frac{k}{3} - 5 = 0 \\ \\ \frac{k}{3} - 8 = 0 \\ \\ \frac{k}{3} = 0 + 8 \\ \\ k = 8 \times 3 \\ \\ k = 24$