Question

if -1/3 is one of the zeroes of polynomial 9x^2-kx-5, then the value of k is?

Answer 1

Here's your Answer according to your question..if -1/3 is one of the zeroes of polynomial 9x^2-kx-5, then the value of k is?

Step by Step Solution :

Forgive my mistakes if there any.

Thanks.

Answer 2

Given : -1/3 is one of the zeroes of polynomial 9x^2-kx-5

To Find :  value of k

Solution:

-1/3 is one of the zeroes of polynomial 9x²-kx-5

that means substituting x = - 1/3  will lead polynomial to zero

Hence

9(-1/3)² - k(-1/3) - 5 = 0

=> 1 + k/3 - 5 = 0

=> k/3 = 4

=> k = 12

value of k = 12

9x^2-12x-5

=9x² -15x + 3x - 5

= 3x(3x  -5 ) + 1(3x - 5)

= (3x  + 1)(3x - 5)

x   = -1/3  , 5/3

Verified

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