Question

If 1/3 is substracted from a number and the difference iss multiplied by 5, the result is twice the given number. What is the number.

Answer 1

Answer:

$\underline{\bigstar\:\:\textsf{According to the Question :}}$

$\dashrightarrow\tt\:\:\bigg(Number-\dfrac{1}{3}\bigg)\times 5=Twice\:of\:Number\\\\\\\dashrightarrow\tt\:\:\bigg(Number-\dfrac{1}{3}\bigg)\times 5=2 \times Number\\\\\\\dashrightarrow\tt\:\:\bigg(\dfrac{3Number - 1}{3}\bigg)\times 5=2Number\\\\\\\dashrightarrow\tt\:\:(3Number - 1)5 = 3(2Number)\\\\\\\dashrightarrow\tt\:\:15Number - 5 = 6Number\\\\\\\dashrightarrow\tt\:\:15Number - 6Number = 5\\\\\\\dashrightarrow\tt\:\:9Number = 5\\\\\\\dashrightarrow\:\:\underline{\boxed{\tt Number = \dfrac{5}{9}}}$

Answer 2

Given:-

• ⅓ is substracted from a number and difference is multiplied by 5, result is twice the given number.

To find:-

• What's the number?

Solution:-

Let the number be y.

${\underline{\bigstar{\textsf{\: According to Question : — }}}}\\\\\longrightarrow\sf \: \: 5 \bigg(y - \dfrac{1}{3} \bigg) = 2y \\\\\longrightarrow\sf \: \: 5 \bigg(\dfrac{3y - 1}{3} \bigg) = 2y \\\\\longrightarrow\sf \: \: \dfrac{5(3y - 1)}{3} = 2y \\\\\qquad\scriptsize\sf{ \big [\because Cross \: multiplicating \big ] } \\\\\longrightarrow\sf \: \: 15y - 5 = 6y \\\\\longrightarrow\sf \: \: 15y - 6y = 5 \\\\\longrightarrow\sf \: \: 9y = 5 \\\\\longrightarrow\: \: \large\underline{\boxed{\sf\blue{y = \dfrac{5}{9} }}} \\\\\\\therefore\underline{\textsf{Given number is = {\textbf{ \dfrac{5}{9} }}}}$