Question

if (1,3)is the solution of 4x+ky+13=0 then find the value of k​

Answer 1

$\it{answer}$

4x+ky+13=0

Here x = 1 and y = 3

• Let us put the value of x and y in equation to get the answer.

• 4x+ky+13=0
• 4(1) + k(3) + 13 = 0
• 4 + 3k + 13 = 0
• 17 + 3k = 0
• 3k = -17
• k = -17/3

Answer 2

Step-by-step explanation:

$\bigstar{\underline{\underline{{\sf\ \red{ Given:-}}}}}$

The value of :-

• x = 1
• y = 3

$\bigstar{\underline{\underline{{\sf\ \red{ To \: find:-}}}}}$

The value of k.

$\bigstar{\underline{\underline{{\sf\ \red{ Solution:-}}}}}$

$4x + ky + 13 = 0 \\ 4(1) + k(3) + 13 = 0 \\ 4 + 3k + 13 = 0 \\ 3k + 17 = 0 \\ 3k = - 17 \\ k = \frac{ - 17}{3}$

Therefore, The value of k is -17/3.