If 1/3 is the zero of the polynomial 3x²+bx+5 then the value of b=_____
Answers
Answered by
16
Answer:
b=-16
Step-by-step explanation:
zero of polynomial 3x^2+bx+5=1/3
therefore x=1/3
substituting value of x in the polynomial
3(1/3)^2+b(1/3)+5
=3(1/9)+b/3+5
=1/3+b/3+5
=1+b+15/3
=16+b/3
16+b/3=0
16+b=0×3
16+b=0
b=-16
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Answered by
1
Answer:b=-16
Step-by-step explanation:
p(x) =3x²+bx+5
p(1/3)= 3(1/3)²+b(1/3) +5
3(1/9)+b/3+5
1/3+b/3+5 —multiply by 3
(1/3)×3+(b/3)×3+5×3
1+b+15
b+16 =0
b=-16
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