Math, asked by ashley1242005, 9 months ago

If 1/3 is the zero of the polynomial 3x²+bx+5 then the value of b=_____​

Answers

Answered by aadya74
16

Answer:

b=-16

Step-by-step explanation:

zero of polynomial 3x^2+bx+5=1/3

therefore x=1/3

substituting value of x in the polynomial

3(1/3)^2+b(1/3)+5

=3(1/9)+b/3+5

=1/3+b/3+5

=1+b+15/3

=16+b/3

16+b/3=0

16+b=0×3

16+b=0

b=-16

Hope it helps you!

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Answered by anishagawas2007
1

Answer:b=-16

Step-by-step explanation:

p(x) =3x²+bx+5

p(1/3)= 3(1/3)²+b(1/3) +5

 3(1/9)+b/3+5

1/3+b/3+5 —multiply by 3

 (1/3)×3+(b/3)×3+5×3

 1+b+15

 b+16 =0

 b=-16

hope u liked it



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