Question

If -1/3 is zero of polynomial 27x3-ax2-x+3 then find the value of 'a'

Answer 1

Answer:

Step-by-step explanation:

Hi,

We have one xero of the polynomial p(x) = $27x^{3} -ax^{2} -x+3 = 0$

to be $-1/3$

So $x = -1/3$

$p(-1/3) = 27 * (-1/3)^{3} - a*(-1/3 )^{2} -(-1/3) +3 = 0\\27 * (-1/27) - a*(1/9) +1/3 +3 = 0\\-1 - a/9 +1/3 +3 = 0\\(-9 - a+3 +27)/9 = 0\\(21- a)/9 = 0\\21- a = 0\\a = 21$

So the value of a is 21