Question

if 1/3 of 100g of 27%aqueous sugar solution is taken in a beaker and 10 g of sugar is added to it, the concentration of resulting sugar will be what? ​

Answer 1

Answer:

/3 of 100g of solution contains 27% of sugar

So, 100/3*27% =100*9%=9g of sugar

Now, it is given that 10g of sugar is added again

Into the solution,

So, total amount of solution

100/3+10=130/3g of solution

Because 9g of sugar is contained by 100/3g of solution , which is given so I added only 10g of sugar to the solution.

Therefore ,

Required new concerntration of sugar in 130/3g of solution,

AtQ: 9+10 =19(total sugar )

19/130/3 *%=19*3/130*%=57/130*%=43.84%.

So the answer is 43.84%

Answer 2

Answer:

1/3 of 100g of solution contains 27% of sugar

So, 100/3*27% =100*9%=9g of sugar

Now, it is given that 10g of sugar is added again

Into the solution,

So, total amount of solution

100/3+10=130/3g of solution

Because 9g of sugar is contained by 100/3g of solution , which is given so I added only 10g of sugar to the solution.

Therefore ,

Required new concerntration of sugar in 130/3g of solution,

AtQ: 9+10 =19(total sugar )

19/130/3 *%=19*3/130*%=57/130*%=43.84%.

So the answer is 43.84%