If 1/3 of a number exceeds it's 2/7 by 1, find the number.
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let the number =x
1/3 of a number = x/3
2/7 of the number = 2x/7
given
1/3 of a number exceeds its 2/7 by 1
x/3 - 2x/7 =1
do the lcm
lcm = 3*7 =21
(7x-6x)/21 =1
⇒x/21 =1
∴ x= 21
required number = x =21
Step-by-step explanation:
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