Math, asked by vikasAttrish, 1 year ago

if 1/3 of a number exceeds its 2/7 bu 1, find the number?

Answers

Answered by Raghav3333
2
hye

=======================

let the number be x 

1/3 of a number exceeds its 2/7 by 1

lets form an equation

=> 
 \frac{1x}{3} = \frac{2x}{7}  +1

=>\frac{1x}{3} - \frac{2x}{7} =1

=>\frac{7x}{21} - \frac{6x}{21} =1

=>\frac{1x}{21}  =1

=>1x = 21*1

=> 21 

=====================

hope it helps u .......

vikasAttrish: thanks
Answered by DIVYCHOUDHARY2005
0
let the number be x
1/3*x-2/7*x=1
x/3-2x/7=1

l.c.m. of 3 and 7=21
(7x-6x)/21=1
x/21=1
x=21*1
x=21




hope it helped you
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