if 1 / 3 of a number exceeds its 2 divided by 7 by 1 find the number
Answers
Answered by
7
Let the number be x,
According to the question ,
x/3 = 2x/7 + 1
x/3 = (2x + 7)/7
7x =3(2x + 7)
7x = 6x + 21
7x - 6x = 21
x = 21
Required number is 21
i hope this will help you
(-:
According to the question ,
x/3 = 2x/7 + 1
x/3 = (2x + 7)/7
7x =3(2x + 7)
7x = 6x + 21
7x - 6x = 21
x = 21
Required number is 21
i hope this will help you
(-:
mayankj2002:
poor ans
Answered by
5
Heya ✋
Let see your answer !!!!!
Let the required number be x. Then,
according to question,
x/3 = 2x/7 + 1
=> x/3 - 2x/7 = 1
=7x - 6x/21 = 1
= x = 21
Hence, the required number is 21.
Thanks :))))
Let see your answer !!!!!
Let the required number be x. Then,
according to question,
x/3 = 2x/7 + 1
=> x/3 - 2x/7 = 1
=7x - 6x/21 = 1
= x = 21
Hence, the required number is 21.
Thanks :))))
Similar questions