Question

if 1/3,x,x2,9 are in gp then value of x2 is

Answer 1

 If [math]a,b [/math]and [math]c[/math] are in G.P., [ math]b^2 = ac[/math]. ... If we consider value of c as (-4) then series will be (-4),(-6),(-9),(-27/2) and so ...

Answer 2

Answer:

$x^2=9^{\frac{2}{3}$

Step-by-step explanation:

Given : $\frac{1}{3},x,x^2,9$ are in gp

To Find : $x^2$

Solution :

Since they are in Gp

So, they have common ratio

So, $r=\frac{9}{x^2}=\frac{x^2}{x}$

$9x=x^4$

$9=x^3$

$9^{\frac{1}{3}=x$

Squaring both sides

$9^{\frac{2}{3}=x^2$

Hence $x^2=9^{\frac{2}{3}$