If -1+√3i=re^itheta, then theta=
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Answer:
taking log on both sides
log(-1+/3i)=log(re^itheta)
log(-1+/3i)=itheta[log(re)]
log(-1+/3i)÷[log(re)]i=there
log(-1+/3i-re)÷i=theta
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