If -1+√3i=re^itheta, then theta
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-1+√3i=re^itheta
L.H.S
multiply and divide with 2 and take - common
-2(1/2-√3/2i)
-2(cos60°- isin60°)
-2e^i60°
comparing it with R.H.S
we get theta = 60°
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