Question

If 1/3is a zero of the polynomial. Find k.
$3x^{3} - 4x ^{2} - 17c - k$
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Answer 1

Let

$f(x) = 3 {x}^{3} - 4 {x}^{2} - 17x - k$

Then,

$f( \frac{1}{3} ) = 0 \\ = > \frac{3}{27} - \frac{4}{9} - \frac{17}{3} - k = 0 \\ = > \frac{1 - 4 - 51 - 9k}{9} = 0 \\ = > 1 - 55 - 9k = 0 \\ = > - 9k = 54 \\ = > k = - 6$

HOPE THIS COULD HELP!!!