Question

If 1/3log 343+1/5log32+logx=log 70 then find x

Answer 1

Step-by-step explanation:

Hey Dear Your Answer is here

1/3 log 343 + 1/5 log32 + logx = log70

1/3 log7^3 + 1/5 log2^5 + logx = log70

3/3 log7 + 5/5 log2 + logx = log70

log7 + log2 + logx = log70

log(7*2*x) = log70

Taking exponential both side to remove log

14x=70

Hence x=5

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