Math, asked by dy607483, 6 months ago

if 1/3of a number exceeds it's 2/7 by 1, find the number​

Answers

Answered by adeeba78692
2

Answer:

the number is 7

Step-by-step explanation:

Let the number be x

(1/3)x=(2/7)x+1

(1/3)x-(2/7)x=1

{(7-6)/7}x=1

1/7x=1

x=7

Answered by Anonymous
58

Let the number be ' n '.

1 / 3 of a number = n / 3

2 / 7 of the number = 2n / 7

1 / 3 of number exceeds its 2 / 7 by 1 .

Exceeds = increases. so ( + )

1 / 3 n = ( 2 / 7 n ) + 1

( 1 / 3 - 2 / 7 ) n = 1 LCM = 21

7 - 6 n / 21 = 1

n / 21 = 1

n = 21 .

.

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