Question

If 1/3rd of HI decomposes at a particular temperature. Then Kc for the reaction 2HI(g) ===` H2(g) + I2(g) is :
​

Answer 1

Explanation:

Given 1/3 HI decomposes to give 1/6 of H

2

and I

2

each.

2HI⇌H

2

+I

2

At equilibrium:

K

c

=

[HI]

2

[H

2

][I

2

]

→K

c

=

3

2

×

3

2

3

1

×

3

1

K

c

=

4

1