Question

if 1+4=5, 7+5=42 and 4+6=28 ,find the value of 8+11.​

Answer 1

Answer:

⊕:N×N→N s.t. (n,m)↦n(m+1)

Then 1⊕4=1×(4+1)=1×5=5, 2⊕5=2×6=12, 3⊕6=3×7=21, and 8⊕11=8×12=96

Answer 2

Answer:

1×4+1=5

7×5+1=42

4×6+1=28

8×11+1=96

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