if 1+4+7+10..........x=287 ,find the value of x
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Sn = n/2 [2a +(n-1)d]
287 = n/2 [2*1 + (n-1)3]
574 = n(2+3n-3)
3n^2 - n -574
n = 14
Sn = n/2(a+l)
287 = 14/2(1+x)
287/7 = x+1
41 -1 = x
so x = 40
287 = n/2 [2*1 + (n-1)3]
574 = n(2+3n-3)
3n^2 - n -574
n = 14
Sn = n/2(a+l)
287 = 14/2(1+x)
287/7 = x+1
41 -1 = x
so x = 40
phoenix55:
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