If 1+4+7+10+ +x equal 287
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a=1, d=7-4=3,Sn=287,n=?
Sn =n/2{2a+(n-1)d]
287 =n/2 [2×1+(n-1)3]
287 =n/2[2+3n-3]
287 = n/2(-1+3n)
574 =-n+3n^2
3n^2-n-574=0
3n^2-42n+41n-574=0
3n(n-14)+41(n-14)=0
(n-14)(3n+41)=0
n-14=0,3n+41=0
n=14,n=-41/3(which is not possible)
so n=14
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