Math, asked by shaheenparveen2999, 9 months ago

if 1 +4+7+10+.....+x287,then value of x is

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Answered by munnipandey10084

Answer:

Step-by-step explanation:

Here,givena=1d=4−1=3and,sn=287Now,sn=2n(2a+(n−1)d)⇒287=2n(2×1+(n−1)3)⇒287=2n(2+3n−3)⇒574=n(3n−1)⇒574=3n2−n⇒3n2−n−574=0onsolvingthequadraticequatonusingformulan=2a−b±b2−4acWegetn=14&3−41[doesnotexist]so,n=14Now,sn=2n(a+1)⇒287=2.

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