If 1.4 g of Calcium oxide is formed by the complete decomposition of Calcium carbonate, then the
amount of Calcium carbonate taken and the amount of Carbon dioxide formed will be respectively
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Chemical reaction for decomposition of calcium carbonate is :
CaCO
3
→CaO+CO
2
Molar mass of CaCO
3
=100g/mol
Molar mass of CaO=56g/mol
Molar mass of CO
2
=44g/mol
According to law of conservation of mass:
Mass of CaCO
3
= Mass of CaO + Mass of CO
2
If we have one mole of calcium carbonate it will decompose to give one mole of calium oxide and one mole of carbon dioxide.
56 g of CaO is obtained from decomposition of 100 g of CaCO
3
.
So 1.4 g of CaO is obtained from decomposition of [(100×1.4)÷56=2.5g] of CaCO
3
.
Mass of CO
2
= (2.5−1.4) g = 1.1 g
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