If =
1/
√5−2
then find the value of x²-1/x² and x³+1/x³
*FIRST ANSWER WILL GET A FOLLOWER*
Answers
Answered by
0
Answer:
x= √5 - 2
⇒ 1/x = 1/ √5 - 2
⇒ 1/x = 1/ √5 - 2 × √5 + 2/ √5 + 2
⇒ 1/x = √5 + 2 / (√5)² - (2)²
⇒ 1/x = √5 + 2 / 5 - 4
⇒ 1/x = √5 + 2
Now,
x + 1/x = √5 - 2 + √5 + 2
x + 1/x = 2√5
And, on squaring both sides,
(x + 1/x )² = (2√5) ²
⇒ x² + 1 / x² + 2 = 20
⇒ x² + 1 / x² = 20 - 2
⇒ x² + 1 / x² = 18
Similar questions