Chemistry, asked by vku82917, 4 months ago

if 1.5 g of koh is present in 500ml. calculate the molarity

Answers

Answered by pankajdhakal

1

Explanation:

given mass of potassium hydroxide = 1.5 g

molecular mass of potassium hydroxide = 39+16+1 = 56

volume of solution = 500 ml

molarity = wkoh×1000/Mkoh × 500

= 0.04

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